# Is right triangle or not

If right triangle ABC, have sides a=13, b=11.5, c=22.5. Find area.

Correct result:

A =  54.415

#### Solution:

$a=13 \ \\ b=11.5 \ \\ c=22.5 \ \\ \ \\ c_{1}=\sqrt{ a^2+b^2 }=\sqrt{ 13^2+11.5^2 } \doteq 17.3566 \ \\ c_{1}<>c \ \\ \ \\ s=\dfrac{ a+b+c }{ 2 }=\dfrac{ 13+11.5+22.5 }{ 2 }=\dfrac{ 47 }{ 2 }=23.5 \ \\ \ \\ A=\sqrt{ s \cdot \ (s-a) \cdot \ (s-b) \cdot \ (s-c) }=\sqrt{ 23.5 \cdot \ (23.5-13) \cdot \ (23.5-11.5) \cdot \ (23.5-22.5) }=3 \ \sqrt{ 329 }=54.415$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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