Z7-1-3 MO 2018

Grandfather prepared a pile of hazelnuts for his six grandchildren with the instruction that they should divide them somehow. First came Adam, who took half for himself, took one more nut, and left. The same was done by the second Bob, the third Cyril, the fourth Dano, and also the fifth Edo. Only Ferko sadly looked at the empty table; no nut was left for him. How many nuts were originally on the pile?

Final Answer:

n =  62

Step-by-step explanation:


E = (n-A-B-C-D)/2+1
D = (n-A-B-C)/2+1
C = (n-A-B)/2+1
B = (n-A)/2+1
A = n/2+1
n = A+B+C+D+E

e = (n-A-B-C-D)/2+1
D = (n-A-B-C)/2+1
C = (n-A-B)/2+1
B = (n-A)/2+1
A = n/2+1
n = A+B+C+D+e

A+B+C+D+2e-n = 2
A+B+C+2D-n = 2
A+B+2C-n = 2
A+2B-n = 2
2A-n = 2
A+B+C+D+e-n = 0

Pivot: Row 1 ↔ Row 5
2A-n = 2
A+B+C+2D-n = 2
A+B+2C-n = 2
A+2B-n = 2
A+B+C+D+2e-n = 2
A+B+C+D+e-n = 0

Row 2 - 1/2 · Row 1 → Row 2
2A-n = 2
B+C+2D-0.5n = 1
A+B+2C-n = 2
A+2B-n = 2
A+B+C+D+2e-n = 2
A+B+C+D+e-n = 0

Row 3 - 1/2 · Row 1 → Row 3
2A-n = 2
B+C+2D-0.5n = 1
B+2C-0.5n = 1
A+2B-n = 2
A+B+C+D+2e-n = 2
A+B+C+D+e-n = 0

Row 4 - 1/2 · Row 1 → Row 4
2A-n = 2
B+C+2D-0.5n = 1
B+2C-0.5n = 1
2B-0.5n = 1
A+B+C+D+2e-n = 2
A+B+C+D+e-n = 0

Row 5 - 1/2 · Row 1 → Row 5
2A-n = 2
B+C+2D-0.5n = 1
B+2C-0.5n = 1
2B-0.5n = 1
B+C+D+2e-0.5n = 1
A+B+C+D+e-n = 0

Row 6 - 1/2 · Row 1 → Row 6
2A-n = 2
B+C+2D-0.5n = 1
B+2C-0.5n = 1
2B-0.5n = 1
B+C+D+2e-0.5n = 1
B+C+D+e-0.5n = -1

Pivot: Row 2 ↔ Row 4
2A-n = 2
2B-0.5n = 1
B+2C-0.5n = 1
B+C+2D-0.5n = 1
B+C+D+2e-0.5n = 1
B+C+D+e-0.5n = -1

Row 3 - 1/2 · Row 2 → Row 3
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
B+C+2D-0.5n = 1
B+C+D+2e-0.5n = 1
B+C+D+e-0.5n = -1

Row 4 - 1/2 · Row 2 → Row 4
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
C+2D-0.25n = 0.5
B+C+D+2e-0.5n = 1
B+C+D+e-0.5n = -1

Row 5 - 1/2 · Row 2 → Row 5
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
C+2D-0.25n = 0.5
C+D+2e-0.25n = 0.5
B+C+D+e-0.5n = -1

Row 6 - 1/2 · Row 2 → Row 6
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
C+2D-0.25n = 0.5
C+D+2e-0.25n = 0.5
C+D+e-0.25n = -1.5

Row 4 - 1/2 · Row 3 → Row 4
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
2D-0.125n = 0.25
C+D+2e-0.25n = 0.5
C+D+e-0.25n = -1.5

Row 5 - 1/2 · Row 3 → Row 5
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
2D-0.125n = 0.25
D+2e-0.125n = 0.25
C+D+e-0.25n = -1.5

Row 6 - 1/2 · Row 3 → Row 6
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
2D-0.125n = 0.25
D+2e-0.125n = 0.25
D+e-0.125n = -1.75

Row 5 - 1/2 · Row 4 → Row 5
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
2D-0.125n = 0.25
2e-0.0625n = 0.125
D+e-0.125n = -1.75

Row 6 - 1/2 · Row 4 → Row 6
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
2D-0.125n = 0.25
2e-0.0625n = 0.125
e-0.0625n = -1.875

Row 6 - 1/2 · Row 5 → Row 6
2A-n = 2
2B-0.5n = 1
2C-0.25n = 0.5
2D-0.125n = 0.25
2e-0.0625n = 0.125
-0.03125n = -1.9375


n = -1.9375/-0.03125 = 62
e = 0.125+0.0625n/2 = 0.125+0.0625 · 62/2 = 2
D = 0.25+0.125n/2 = 0.25+0.125 · 62/2 = 4
C = 0.5+0.25n/2 = 0.5+0.25 · 62/2 = 8
B = 1+0.5n/2 = 1+0.5 · 62/2 = 16
A = 2+n/2 = 2+62/2 = 32

A = 32
B = 16
C = 8
D = 4
e = 2
n = 62

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