Paratrooper

After the parachute is opened, the paratrooper drops to the ground at a constant speed of 2 m/s, with the sidewinding at a steady speed of 1.5 m/s. Find:

a) the magnitude of its resulting velocity concerning the ground,
b) the distance of his land from a tree over which the airplane dropped it at an altitude of 800 m above the ground (AGL).

Final Answer:

v =  2.5 m/s
x =  600 m

Step-by-step explanation:

$$\begin{gathered} v_1=2\text{m/s} \\ {v}_2=1.5\text{m/s} \\ v=\sqrt{v_1^2+v_2^2}=\sqrt{2^2+1.5^2}=2.5\text{m/s} \end{gathered}$$

$$\begin{gathered} h=800\text{m} \\ t=h/v_1=800/2=400\text{s} \\ x=t\cdot v_2=400\cdot 1.5=600\text{m} \end{gathered}$$

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