After the parachute is opened, the paratrooper drops to the ground at a constant speed of 2 m/s, with the sidewinding at a steady speed of 1.5 m/s. Find:

a) the magnitude of its resulting velocity with respect to the ground,
b) the distance of his land from a tree over which it was dropped at an altitude of 800 m above the ground (AGL).

Correct result:

v =  2.5 m/s
x =  600 m


v1=2 m/s v2=1.5 m/s  v=v12+v22=22+1.52=52=52 m/s=2.5 m/s
h=800 m t=h/v1=800/2=400 s  x=t v2=400 1.5=600 m

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