Penny free fall

A man drops a penny from the top of a 500m tall building. After t seconds, the penny has fallen a distance of s meters, where s(t)=500-5t2. Determine the average velocity between 1s and 5s.

Correct answer:

v =  30 m/s

Step-by-step explanation:

s(t)=5005t2 t1=1 s t2=5 s  v =  dt ds   v(t) = 5 2 t1 = 10   t  v1=5 2 t1=5 2 1=10 m/s v2=5 2 t2=5 2 5=50 m/s  v=2v1+v2=210+50=30 m/s

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