Sea water

Seawater contains about 4.3% salt. How many dm3 of distilled water we must pour into 5 dm3 of sea water to get water with 1.8% salt?


V =  6.94 dm3


4.3% 5=1.8% (5+V) 4.3/100 5=1.8/100 (5+V)  4.3 5=1.8 (5+V)  1.8V=12.5  V=125186.944444 =6.94 dm34.3 \% \cdot \ 5 = 1.8 \% \cdot \ (5+V) \ \\ 4.3/100 \cdot \ 5 = 1.8/100 \cdot \ (5+V) \ \\ \ \\ 4.3 \cdot \ 5 = 1.8 \cdot \ (5+V) \ \\ \ \\ 1.8V = 12.5 \ \\ \ \\ V = \dfrac{ 125 }{ 18 } \doteq 6.944444 \ \\ = 6.94 \ dm^3

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