Four numbers

I am a four-digit number, no zeros, in which the first number is five times the last, the second is four more than the first and three times the third, and the third is two more than the last and two less than the first.

Correct answer:

x =  5931

Step-by-step explanation:

$$\begin{gathered} x=abcd \\ a=5d \\ b=4+a \\ b=3c \\ c=2+d=a-2 \\ a\ne 0a\ne 10 \\ a=5\cdot d \\ d=1 \\ a=5\cdot d=5\cdot 1=5 \\ b=4+a=4+5=9 \\ c=b/3=9/3=3 \\ x=5931 \end{gathered}$$

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