Marriage sttus

In our city, there are 3/5 of the women married to 2/3 of the men. Find what part of the population is free.

Correct result:

p =  0.3684

Solution:

$$\begin{gathered} z=3000 \\ 3\mathrm{/}5\cdot z=2\mathrm{/}3\cdot m \\ z=3000 \\ 10m-9z=0 \\ m=2700 \\ z=3000 \\ v=3\mathrm{/}5\cdot z=3\mathrm{/}5\cdot 3000=1800 \\ p={\displaystyle \frac{m+z-2\cdot v}{m+z}}={\displaystyle \frac{2700+3000-2\cdot 1800}{2700+3000}}={\displaystyle \frac{7}{19}}=0.3684 \end{gathered}$$

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