Spherical segment

The spherical segment with height h=1 has a volume V=223. Calculate the radius of the sphere of which is cut this segment.

Correct answer:

r =  71.32

Step-by-step explanation:

$$\begin{gathered} h=1 \\ V=223 \\ V={\displaystyle \frac{1}{3}}\pi h^2(3r-h) \\ r={\displaystyle \frac{V}{\pi \cdot h^2}}+h\mathrm{/}3={\displaystyle \frac{223}{3.1416\cdot 1^2}}+1\mathrm{/}3=71.32 \end{gathered}$$

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Math student

Can you show the step by step process

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