A sample 2

A sample of underweight babies was fed a special diet, and the following weight gains (lbs) were observed at the end of three months: 6.7, 2.7, 2.5, 3.6, 3.4, 4.1, 4.8, 5.9, and 8.3. Find the variance. (Round off to the nearest hundredths)

Correct answer:

v =  3.8125

Step-by-step explanation:

6.7,2.7,2.5,3.6,3.4,4.1,4.8,5.9,8.3 n=9 s=6.7+2.7+2.5+3.6+3.4+4.1+4.8+5.9+8.3=42  μ=ns=942=314=4324.6667  s2=(6.7μ)2+(2.7μ)2+(2.5μ)2+(3.6μ)2+(3.4μ)2+(4.1μ)2+(4.8μ)2+(5.9μ)2+(8.3μ)2=(6.7314)2+(2.7314)2+(2.5314)2+(3.6314)2+(3.4314)2+(4.1314)2+(4.8314)2+(5.9314)2+(8.3314)2=261=3021=30.5  v=n1s2=n1261=9130.5=1661=31613=3.8125

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