Rectangle pool

The cube-shaped pool is 50 m long and 16 m wide. They poured 12,000 hl of water into it. Calculate the surface area of the pool that is wetted by water.

Final Answer:

S =  998 m²

Step-by-step explanation:

$$\begin{gathered} a=50\text{m} \\ b=16\text{m} \\ V=12000\text{hl}\to {\text{m}}^3=12000:10{\text{m}}^3=1200{\text{m}}^3 \\ {S}_1=a\cdot b=50\cdot 16=800{\text{m}}^2 \\ V=abc=S_1\cdot c \\ c=\frac{V}{S_1}=\frac{1200}{800}=\frac{3}{2}=1.5\text{m} \\ o=2\cdot (a+b)=2\cdot (50+16)=132\text{m} \\ {S}_2=c\cdot o=1.5\cdot 132=198{\text{m}}^2 \\ S=S_1+S_2=800+198=998{\text{m}}^2 \end{gathered}$$

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