Triangle height vertices

Calculate the height of side b (v_b) of triangle ABC with vertices A[4;1;3] B[2;3;3] and C[1;1;3].

Final Answer:

v2 =  2

Step-by-step explanation:

A=(4,1,3) B=(2,3,3) C=(1,1,3)  Az=Bz=Cz  a=BC a=dist(B,C)=BC=(BxCx)2+(ByCy)2=(21)2+(31)2=52.2361  b=AC b=dist(A,C)=AC=(AxCx)2+(AyCy)2=(41)2+(11)2=3  c=AB c=dist(A,B)=AB=(AxBx)2+(AyBy)2=(42)2+(13)2=2 22.8284  s=2a+b+c=22.2361+3+2.82844.0322 S=s (sa) (sb) (sc)=4.0322 (4.03222.2361) (4.03223) (4.03222.8284)=3  S = 2b v2  v2=b2 S=32 3=2



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geometryalgebraarithmeticplanimetricsUnits of physical quantitiesGrade of the word problem

 
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