Sphere floating

Will float a hollow iron ball with an outer diameter d1 = 20cm and an inside diameter d2 = 19cm in the water? The iron density is 7.8 g/cm 3. (Instructions: Calculate the average sphere density and compare with the density of the water. )

Correct result:

x =  0

Solution:

d1=20 cm d2=19 cm ρ=7.8 g/cm3 v=1 g/cm3  r1=d1/2=20/2=10 cm r2=d2/2=19/2=192=9.5 cm  V1=43 π r13=43 3.1416 1034188.7902 cm3 V2=43 π r23=43 3.1416 9.533591.364 cm3   m=ρ (V1V2)=7.8 (4188.79023591.364)4659.9244 g  ρ2=mV1=4659.92444188.79021.1125 g/cm3  ρ2>v  x=0



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