# Efficiency

A certain device consumes 28 kW and delivers 14 kW. Find its efficiency.

p =  50 %

### Step-by-step explanation:

$p=\frac{14}{28}\cdot 100\mathrm{%}=50\mathrm{%}$ Did you find an error or inaccuracy? Feel free to write us. Thank you! Tips to related online calculators
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