Isosceles triangle 9
There is an isosceles triangle ABC where AB= AC. The perimeter is 64cm, and the altitude is 24cm. Find the area of the isosceles triangle.
Correct answer:
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Steve
No, your solution starts with h=25cm, but the question says that h=24cm.
So, looking at one-half of the isosceles triangle, x2 + 242 = (32-x)2 solves to x=7cm, which gives the area of the isosceles triangle as 7x24 = 168cm2
So, looking at one-half of the isosceles triangle, x2 + 242 = (32-x)2 solves to x=7cm, which gives the area of the isosceles triangle as 7x24 = 168cm2
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