Isosceles triangle

What are the angles of an isosceles triangle ABC if its base is long a=5 m and has an arm b=4 m.

Correct result:

α =  77.4 °
β =  51.3 °
γ =  51.3 °

Solution:

$\beta =\gamma =\left(180-\alpha \right)\mathrm{/}2=51.{3}^{\circ }$

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