Isosceles triangle

What are the angles of an isosceles triangle ABC if its base is long a=5 m and has an arm b=4 m.

Correct result:

α =  77.4 °
β =  51.3 °
γ =  51.3 °

Solution:

sinα2=a/2b α=2arcsina/2b=2arcsin5/24=77.4
β=γ=(180α)/2=51.3
γ=(1802 180πasin(5/2/4))/2=51.3



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