Medians of isosceles triangle

The isosceles triangle has a base ABC |AB| = 16 cm and 10 cm long arm. What are the length of medians?

Correct result:

t₁ =  6 cm
t₂ =  12.3693 cm
t₃ =  12.3693 cm

Solution:

$t_1=\sqrt{10^2-8^2}=6\text{ cm}$

Try calculation via our triangle calculator.

$t_2=\sqrt{16^2+5^2-2\cdot 16\cdot 5\cdot \cos (\arcsin (6\mathrm{/}10))}=12.3693\text{ cm}$

$t_3=t_2=12.3693\text{ cm}$

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