Medians of isosceles triangle

The isosceles triangle has a base ABC |AB| = 16 cm and a 10 cm long arm. What is the length of the medians?

Correct answer:

t1 =  6 cm
t2 =  12.3693 cm
t3 =  12.3693 cm

Step-by-step explanation:

c=16 cm a=10 cm  a2 = t12​ + (c/2)2 t1​=a2−(c/2)2​=102−(16/2)2​=6 cm
α=arcsin((c−a)/a)=arcsin((16−10)/10)≐0.6435 rad t2​=c2+(a/2)2−2⋅ c⋅ a/2⋅ cosα​=162+(10/2)2−2⋅ 16⋅ 10/2⋅ cos0.6435​=3 17​=12.3693 cm
t3​=t2​=12.3693=12.3693 cm

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