# Medians of isosceles triangle

The isosceles triangle has a base ABC |AB| = 16 cm and 10 cm long arm. What are the length of medians?

Result

t1 =  6 cm
t2 =  12.369 cm
t3 =  12.369 cm

#### Solution:

$t_1=\sqrt{ 10^{ 2 }-8^{ 2 } }=6 \ \text{cm}$

Try calculation via our triangle calculator.

$t_2=\sqrt{ 16^{ 2 }+5^{ 2 }-2 \cdot \ 16 \cdot \ 5 \cdot \ \cos(\arcsin(6/10)) }=12.369 \ \text{cm}$
$t_3 = t_2 = 12.369 \ \text{cm}$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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