Tanks

Fire tank has cuboid shape with a rectangular floor measuring 13.7 m × 9.8 m. Water depth is 2.4 m. Water was pumped from the tank into barrels with a capacity of 2.7 hl.

How many barrels were used, if the water level in the tank fallen 5 cm? Write the amount of water pumped as percentage.

Result

n =  25
p =  2.08 %

Solution:

V=13.7⋅9.8⋅2.4=322.224 m3 V1=13.7⋅9.8⋅0.05=6.713 m3 V2=2.7 hl=0.27 m3  n=V1V2≐25V = 13.7 \cdot 9.8 \cdot 2.4 = 322.224 \ m^3 \ \\ V_1 = 13.7 \cdot 9.8 \cdot 0.05 = 6.713 \ m^3 \ \\ V_2 = 2.7 \ hl = 0.27 \ m^3 \ \\ \ \\ n = \dfrac{ V_1}{V_2} \doteq 25
p=V1V⋅100=6.713322.224⋅100=2.08%p = \dfrac{ V_1}{ V } \cdot 100 = \dfrac{ 6.713}{ 322.224 } \cdot 100 = 2.08 \%

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