Isosceles trapezoid

Isosceles trapezoid ABCD, AB||CD is given by |CD| = c = 12 cm, height v = 16 cm and |CAB| = 20°.

Calculate area of the trapezoid.

Correct answer:

S =  703.3542 cm²

Step-by-step explanation:

$$\begin{gathered} \tan 20^{\circ }={\displaystyle \frac{v}{a_1}} \\ {a}_1={\displaystyle \frac{16}{\tan 20^{\circ }}}=43.96 \\ {a}_1=c+x \\ x=a_1-c=31.96 \\ a=c+2x=2a_1-c=75.92cm \\ S={\displaystyle \frac{a+c}{2}}v={\displaystyle \frac{v^2}{\tan 20^{\circ }}}=703.3542{\text{cm}}^2 \end{gathered}$$

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