Two workers

Two workers together execute some work in 10 days. The first worker would have done it alone in 20 days. How many days would he have done it alone a second worker?

Final Answer:

t2 =  20

Step-by-step explanation:

t=10 d t1=20 d  t (1/t1+1/t2)=1  t11+t21=t1 t21=t1t11  w=t1t11=101201=202201=2021=201=0.05  t2=1/w=1/201=1:201=1 120=11 20=120=20



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