# Bob and Bobek

At 10h 20min runs Bobek from hat at average speed 12 km/h. At what time must run out Bob at speed 18 km/h to catch him 9 kilometers from the hat?

Result

h = 10:35

#### Solution:

12(t-(10+20/60))=9
18(t-h)=9

720t = 7980
18h-18t = -9

h = 127/12 ≈ 10.583333
t = 133/12 ≈ 11.083333

Calculated by our linear equations calculator.

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