Calculate area of the rectangle if its length is 12 cm longer than its width and length is equal to the square of its width.
Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):
Showing 0 comments:
Be the first to comment!
To solve this example are needed these knowledge from mathematics:
Next similar examples:
- Square and rectangle
Calculate the side of a square which content area equals area of the rectangle having a length of 3 cm greater and by 2 cm smaller than the side of the square.
- Rectangle - area, perimeter
The area of a rectangular field is equal to 300 square meters. Its perimeter is equal to 70 meters. Find the length and width of this rectangle.
- A rectangle
A rectangle has an area of 36 cm2. What could the length and width of rectangle be?
Determine the quadratic equation absolute coefficient q, that the equation has a real double root and the root x calculate: ?
- Variations 4/2
Determine the number of items when the count of variations of fourth class without repeating is 600 times larger than the count of variations of second class without repetition.
- Square root 2
If the square root of 3m2 +22 and -x = 0, and x=7, what is m?
- Quadratic equation
Find the roots of the quadratic equation: 3x2-4x + (-4) = 0.
Equation ? has one root x1 = 8. Determine the coefficient b and the second root x2.
- Theorem prove
We want to prove the sentense: If the natural number n is divisible by six, then n is divisible by three. From what assumption we started?
Determine the discriminant of the equation: ?
- Expression with powers
If x-1/x=5, find the value of x4+1/x4
X+y=5, find xy (find the product of x and y if x+y = 5)
- Evaluation of expressions
If a2-3a+1=0, find (i)a2+1/a2 (ii) a3+1/a3
- Expressions 3
If k(x+6)= 4x2 + 20, what is k(10)=?
- Solve 3
Solve quadratic equation: (6n+1) (4n-1) = 3n2
From how many elements we can create 990 combinations 2nd class without repeating?
- Parametric equation
Find the parametric equation of a line with y-intercept (0,-4) and a slope of -2.