Sphere radius

We reduce the radius of the sphere by 1/3 of the original radius. How much percent does the volume and surface of the sphere change?

Final Answer:

p1 =  70.3704 %
p2 =  55.5556 %

Step-by-step explanation:

r1=1 r2=r1r1/3=11/3=320.6667  V1=34 π r13=34 3.1416 134.1888 V2=34 π r23=34 3.1416 0.666731.2411  p1=100 V1V1V2=100 4.18884.18881.2411=271900%=70.3704%
S1=4π r12=4 3.1416 1212.5664 S2=4π r22=4 3.1416 0.666725.5851  p2=100 S1S1S2=100 12.566412.56645.5851=9500%=55.5556%



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solid geometrybasic operations and conceptsnumbersUnits of physical quantitiesGrade of the word problem

 
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