Sphere radius

The radius of the sphere we reduce by 1/3 of the original radius. How much percent does the volume and surface of the sphere change?

Correct result:

p1 =  70.3704 %
p2 =  55.5556 %

Solution:

r1=1 r2=r1r1/3=11/3=230.6667  V1=43 π r13=43 3.1416 134.1888 V2=43 π r23=43 3.1416 0.666731.2411  p1=100 V1V2V1=100 4.18881.24114.1888=190027=70.3704%
S1=4π r12=4 3.1416 1212.5664 S2=4π r22=4 3.1416 0.666725.5851  p2=100 S1S2S1=100 12.56645.585112.5664=5009=55.5556%



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