Trapezoid ABCD v2

Trapezoid ABCD has a length of bases in ratio 3:10. The area of triangle ACD is 825 dm2. What is the area of trapezoid ABCD?

Correct answer:

S =  1072.5 dm2

Step-by-step explanation:

a/c=3/10 SACD=825=ch/2 h=2SACD/c  S=a+c2h=a+c22SACDc S=(a+c)SACD/c S=SACD(a/c+1)=825(3/10+1) S=1072.5 dm2



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