Pit

Pit has shape of a truncated pyramid with rectangular bases and is 0.8 m deep. The length and width of the pit is the top 3 × 1.5 m bottom 1 m × 0.5 m. To paint one square meter of pit we use 0.6 l of green colour. How many liters of paint is needed when we paint only the sides and bottom of pit?

Correct result:

V =  4.1 l

Solution:

x0=3 m y0=1.5 m  x=1 m y=0.5 m  h=0.8 m  h1=h2+((y0y)/2)2=0.82+((1.50.5)/2)20.9434 m h2=h2+((x0x)/2)2=0.82+((31)/2)21.2806 m  S1=x y=1 0.5=12=0.5 m2  S2=(x+x0) h12=(1+3) 0.943421.8868 m2 S3=(y+y0) h22=(0.5+1.5) 1.280621.2806 m2  S=S1+2 (S2+S3)=0.5+2 (1.8868+1.2806)6.8348 m2  V=0.6 S=0.6 6.8348=4.1 l



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Showing 2 comments:
#
Math student
the process of the answer is not enough clear try to associate it well with the graph

#
Dr Math
yes, the image is only for illustration .... symbols have not the same meaning as in solutions... We re-write steps of solutions to be more clear.

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