The pit has the shape of a truncated pyramid with a rectangular base and is 0.8 m deep. The pit's length and width are the top 3 × 1.5 m bottom 1 m × 0.5 m. To paint one square meter of the pit we use 0.6 l of green color. How many liters of paint are needed when we paint only the sides and bottom of the pit?

Correct result:

V =  4.1 l


x0=3 m y0=1.5 m  x=1 m y=0.5 m  h=0.8 m  h1=h2+((y0y)/2)2=0.82+((1.50.5)/2)20.9434 m h2=h2+((x0x)/2)2=0.82+((31)/2)21.2806 m  S1=x y=1 0.5=12=0.5 m2  S2=(x+x0) h12=(1+3) 0.943421.8868 m2 S3=(y+y0) h22=(0.5+1.5) 1.280621.2806 m2  S=S1+2 (S2+S3)=0.5+2 (1.8868+1.2806)6.8348 m2  V=0.6 S=0.6 6.8348=4.1 l

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Showing 2 comments:
Math student
the process of the answer is not enough clear try to associate it well with the graph

Dr Math
yes, the image is only for illustration .... symbols have not the same meaning as in solutions... We re-write steps of solutions to be more clear.


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