Same force

The trunk of 5m length and 95 kilograms has a center of gravity 2m from the thicker end. The tribe is carried by two men, one at the thicker end. At what distance does the trunk carry a man from the other end to make the same force on it?

Correct result:

x =  1 m

Solution:

$$\begin{gathered} l=5\text{ m } \\ m=95\text{ kg } \\ y=2\text{ m } \\ \mathrm{\Sigma }M=0 \\ {F}_1\cdot y=F_2\cdot (l-y-x)=F_2\cdot (5-2-1)=0 \\ {F}_1=F_2 \\ y=l-y-x \\ x=l-2\cdot y=5-2\cdot 2=1\text{ m} \end{gathered}$$

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