Rectangular base pyramid

Calculate an area of the shell of the pyramid with a rectangular base of 2.8 m and 1.4 m and height 2.5 meters.

Correct result:

S =  11.2807 m2

Solution:

h=2.5 m a=2.8 m b=1.4 m  h1=h2+(b/2)2=2.52+(1.4/2)2≐2.5962 m h2=h2+(a/2)2=2.52+(2.8/2)2≐2.8653 m  S1=a⋅ h12=2.8⋅ 2.59622≐3.6346 m2 S2=b⋅ h22=1.4⋅ 2.86532≐2.0057 m2  S=2⋅ S1+2⋅ S2=2⋅ 3.6346+2⋅ 2.0057=11.2807 m2

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