The new copier is copying a folder of papers 5 minutes faster than the old one. The operator used new, but out of toner and exchange took 5 min at that time copied on the old. The whole work was done in 9 min. How long would the work do only by the old copier?

Correct answer:

t =  11.9 min

Step-by-step explanation:

t595+t5=1 4t+5(t5)=t(t5)  t214t+25=0  a=1;b=14;c=25 D=b24ac=1424125=96 D>0  t1,2=2ab±D=214±96=214±46 t1,2=7±4.898979 t1=11.898979486 t2=2.101020514   Factored form of the equation:  (t11.898979486)(t2.101020514)=0  t>5 t=11.9 min

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