The new copier copying a folder of papers 5 min. faster than the old. The operator used new, but out of toner and exchange took 5 min. In that time copied on the old. The whole work has been done for 9 min. How long would the work done only by old copier?

Correct answer:

t =  11.9 min

Step-by-step explanation:

95t5+5t=1 4t+5(t5)=t(t5)  t214t+25=0  a=1;b=14;c=25 D=b24ac=1424125=96 D>0  t1,2=b±D2a=14±962=14±462 t1,2=7±4.89897948557 t1=11.8989794856 t2=2.10102051443   Factored form of the equation:  (t11.8989794856)(t2.10102051443)=0  t>5 t=11.9 min

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