Iron fence

One field of iron fence consists of 20 iron rods with square cross-section of 1.5 cm side and a long 1 meter. How much weight a field if the density of iron is 7800 kg/m3.

Result

x =  35.1 kg

Solution:

x=20 0.015 0.015 1 7800=35110=35.1  kg x=20 \cdot \ 0.015 \cdot \ 0.015 \cdot \ 1 \cdot \ 7800 = \dfrac{ 351 }{ 10 } = 35.1 \ \text{ kg }



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