Iron pole

What is the mass of pole with the shape of a regular quadrilateral prism with a length of 1 m and a cross-sectional side length of a = 4.5 cm make from iron with density ρ = 7800 kg/m³?

Correct result:

m =  15.795 kg

Solution:

ρ=7800 kg/m3 c=1 m a=4.5 cmm=4.5/100 m=0.045 m V=a2 c=0.0452 181400000.002 m3  m=ρ V=7800 0.002=3159200=15.795 kgρ=7800 \ \text{kg/m}^3 \ \\ c=1 \ \text{m} \ \\ a=4.5 \ cm \rightarrow m=4.5 / 100 \ m=0.045 \ m \ \\ V=a^2 \cdot \ c=0.045^2 \cdot \ 1 \doteq \dfrac{ 81 }{ 40000 } \doteq 0.002 \ \text{m}^3 \ \\ \ \\ m=ρ \cdot \ V=7800 \cdot \ 0.002=\dfrac{ 3159 }{ 200 }=15.795 \ \text{kg}



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