Iron pole

What is the mass of pole with the shape of a regular quadrilateral prism with a length of 1 m and a cross-sectional side length of a = 4.5 cm make from iron with density ρ = 7800 kg/m³?

Correct result:

m =  15.795 kg

Solution:

$$\begin{gathered} \rho =7800{\text{kg/m}}^3 \\ c=1\text{ m } \\ a=4.5\text{ cm}\to \text{ m}=4.5\mathrm{/}100\text{ m}=0.045\text{ m } \\ V=a^2\cdot c=0.045^2\cdot 1={\displaystyle \frac{81}{40000}}\doteq 0.002{\text{m}}^3 \\ m=\rho \cdot V=7800\cdot 0.002={\displaystyle \frac{3159}{200}}={\displaystyle \frac{3159}{200}}\text{ kg}=15.795\text{ kg} \end{gathered}$$

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