In the first basement is more flies than the spiders, the second vice versa. Each basement had spiders and flies together 100 feet. Determine how many could be flies and spiders in the first and second basement.

PS. We only need, when you write how many solutions have this problem.

Correct result:

n =  4


100 = 6m + 8p
[m; p]:

[2; 11]
[6; 8]
[10; 5]
[14; 2]

P= { {[10; 5], [2; 11]},
{[10; 5], [6; 8]},
{[14; 2], [2; 11]},
{[14; 2], [6; 8]}}

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