# Slope of track

Calculate the average slope (in permille and even in degrees) of the rail tracks between Prievidza (309 m AMSL) and Nitrianske Pravno (354 m AMSL), if the track is 11 km long.

Correct result:

s1 =  4.09
s2 =  0.2344 °

#### Solution:

${s}_{2}=\frac{18{0}^{\circ }}{\pi }\cdot \mathrm{arctan}\left(\frac{y}{x}\right)=\frac{18{0}^{\circ }}{\pi }\cdot \mathrm{arctan}\left(\frac{45}{10999.908}\right)=0.234{4}^{\circ }={0}^{\circ }1{4}^{\mathrm{\prime }}4\mathrm{"}$

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