# Slope of track

Calculate the average slope (in permille and even in degrees) of the rail tracks between Prievidza (309 m AMSL) and Nitrianske Pravno (354 m AMSL), if the track is 11 km long.

s1 =  4.09
s2 =  0.2344 °

### Step-by-step explanation:

${s}_{2}=\frac{180\mathrm{°}}{\pi }\cdot \mathrm{arctan}\left(\frac{y}{x}\right)=\frac{180\mathrm{°}}{\pi }\cdot \mathrm{arctan}\left(\frac{45}{10999.908}\right)=0.2344\text{°}=0\mathrm{°}1{4}^{\mathrm{\prime }}4\mathrm{"}$

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