Slope of track

Calculate the average slope (in permille and even in degrees) of the rail tracks between Prievidza (309 m AMSL) and Nitrianske Pravno (354 m AMSL), if the track is 11 km long.

Correct result:

s1 =  4.09
s2 =  0.2344 °

Solution:

s=11 km m=11 1000  m=11000 m y=309354=45 m  x=s2y2=110002452=235 2191 m10999.908 m  s1=1000 yx=1000 4510999.908=4.09 ‰
s2=180πarctan(yx)=180πarctan(4510999.908)=0.2344=0144"



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