# Trapezium

The length of the base and the height size of the base of the trapezium is at ratio 5:3:2, the content area of the trapezium is 128 cm2. Calculate the length of the base and the height of the trapezoid.

Result

a =  18.856
c =  11.314
v =  7.542

#### Solution:

$k=\sqrt{ 128/(5+3+1) } \doteq 3.7712 \ \\ a=5k=5 \cdot \ 3.7712 \doteq 18.8562 \doteq 18.856$
$c=3k=3 \cdot \ 3.7712 \doteq 8 \ \sqrt{ 2 } \doteq 11.3137 \doteq 11.314$
$v=2k=2 \cdot \ 3.7712 \doteq 7.5425 \doteq 7.542$

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