Intersections 3

Find the intersections of the circles
x2 + y2 + 6 x - 10 y + 9 = 0 and
x2 + y2 + 18 x + 4 y + 21 = 0

Correct answer:

x1 =  -1.3335
y1 =  0.2859
x2 =  -7.9135
y2 =  5.9259

Step-by-step explanation:

x2+y2+6 x10 y+9=0 x2+y2+18 x+4 y+21=0  e2e1: (186)x+(4+10)y+(219)=0 y=6/7(x+1)   x2+(6/7(x+1))2+6x10(6/7(x+1))+9=0  x2+(6/7(x+1))2+6 x10(6/7(x+1))+9=0 1.734693877551x2+16.041x+18.306=0  a=1.734693877551;b=16.041;c=18.306 D=b24ac=16.041241.73469387755118.306=130.2857142857 D>0  x1,2=b±D2a=16.04±130.293.469387755102 x1,2=4.62352941±3.2899974232486 x1=1.3335319885161=1.3335 x2=7.9135268350134   Factored form of the equation:  1.734693877551(x+1.3335319885161)(x+7.9135268350134)=0

Our quadratic equation calculator calculates it.

y1=6/7 (x1+1)=6/7 ((1.3335)+1)=0.2859
y2=6/7 (x2+1)=6/7 ((7.9135)+1)=5.9259



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