Truncated cone 6

Calculate the volume of the truncated cone whose bases consist of an inscribed circle and a circle circumscribed to the opposite sides of the cube with the edge length a=1.

Correct result:

V =  0.4469

Solution:

a=1 h=a=1  r1=a/2=1/2=12=0.5 r2=2/2 a=2/2 10.7071  V=π h3 (r12+r1 r2 r22)=3.1416 13 (0.52+0.5 0.7071 0.70712)0.4469   Verifying Solution:  V=π a3 (a2/4+a2/4 2+a2/2) V=π a33 (1/4+2/4+1/2) V=(212+14) π a3=0.4469



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