Probability

A man had 4 coins, some $2, some $1. The coins had a number on one side and a picture on the other. The man flipped them, and the sum of the numbers on the tops of the coins was 1. The probability of this happening was 1/8. What was the probability that if the man had flipped the coins, he would have gotten a sum of 3 on the tops?

Final Answer:

p₃ =  0.25

Step-by-step explanation:

$$\begin{gathered} n=4 \\ {p}_1=\frac{2}{2^4}=\frac{1}{8}=0.125 \\ {p}_3=\frac{4}{2^4}=\frac{1}{4}=0.25 \end{gathered}$$

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