Denisa is preparing for a goldsmith's costume carnival. During the preparations, she thought she would let her hair wipe instead - she would apply a 5 μm thick layer of gold to each hair. How much gold would Denisa need? Assume that all hundred thousand Denise's hair has a length of 0.5 m, a diameter of 60 μm, and a cylinder shape. The density of gold is 19,000 kg·m-3.

Correct answer:

m =  969.9667 g

Step-by-step explanation:

h=19 g/cm3 D2=60/1000/10=5003=0.006 cm r2=D2/2=0.006/2=10003=0.003 cm r1=r2+5/1000/10=0.003+5/1000/10=20007=0.0035 cm V=50 (π r12π r22)=50 (3.1416 0.003523.1416 0.0032)0.0005 cm3  m1=h V=19 0.00050.0097 g m=100000 m1=100000 0.0097=969.9667 g

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
Do you want to convert length units?
Do you know the volume and unit volume, and want to convert volume units?
Tip: Our Density units converter will help you convert density units.
Do you want to convert mass units?

You need to know the following knowledge to solve this word math problem:

We encourage you to watch this tutorial video on this math problem: video1

Related math problems and questions: