Denisa is preparing for a goldsmith's costume carnival. During the preparations, she thought she would let her hair wipe instead - she would apply a 5 μm thick layer of gold to each hair. How much gold would Denisa need? Assume that all hundred thousand Denise's hair has a length of 0.5 m a diameter 60 μm and a cylinder shape. The density of gold is 19,000 kg·m-3.

Correct answer:

m =  969.9667 g

Step-by-step explanation:

h=19 r2=60/1000/10/2=31000=0.003 r1=r2+5/1000/10=0.003+5/1000/10=72000=0.0035 V=50 (π r12π r22)=50 (3.1416 0.003523.1416 0.0032)0.0005 m1=h V=19 0.00050.0097 m=100000 m1=100000 0.0097=969.9667 g

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