Three different dinners A, B, C are served in the motel.
Three 20 members went to motel. Group 1 ordered dinners: A 20 members and their average dinner price in the group was CZK 200. From Group 2, they ordered a A: 10 persons, B 10 dinners, and their average dinner dinner price for the group was 240 CZK. From Group 3, they ordered a 5 persons A dinners, B 5 dinners, a C 10 dinners, and their average dinner price was CZK 270.
Calculate the price of dinner A, B, C.

Correct result:

A =  0
B =  0
C =  0


10A +10B = 20•240
5A+5B+10C = 20•270

3980A+4000B+4000C = 0
4790A+4790B+4800C = 0
5395A+5395B+5390C = 0

A = 0
B = 0
C = 0

Our linear equations calculator calculates it.

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