Pentagonal pyramid

Find the volume and surface of a regular pentagonal pyramid with a base edge a = 12.8 cm and a height v = 32.1 cm.

Correct result:

V =  3016.1483 cm3
S =  1347.0581 cm2

Solution:

a=12.8 cm v=32.1 cm n=5  S1=14 5 (5+2 5) a2=14 5 (5+2 5) 12.82281.883 cm2  V=13 S1 v=13 281.883 32.1=3016.1483 cm3
S1=n a h12  h1=2 S1/n/a=2 281.883/5/12.88.8088 cm  h2=v2+h12=32.12+8.8088233.2867 cm  S2=a h22=12.8 33.28672213.035 cm2  S=S1+n S2=281.883+5 213.035=1347.0581 cm2



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