# Candies

The price for 1 kg of more expensive candies is 125 CZK.
The price for 1 kg of cheaper candy is 100 CZK.
We mix two different mixtures of candy.

A) The first mixture contains 2 kg more expensive and 0.5 kg cheaper candy. Calculate the price for 1 kg of the mixture.
B) The second mixture contains 2 kg of more expensive candy and several kg of cheaper candy. The price per 1 kg of this mix is 110 CZK. Calculate how many kilos of cheaper candy contains the second mixture.

Correct result:

A =  120 Kc/kg
B =  3 kg

#### Solution:

$a=125 \ \\ b=100 \ \\ A=(2 \cdot \ a+0.5 \cdot \ b)/(2+0.5)=(2 \cdot \ 125+0.5 \cdot \ 100)/(2+0.5)=120 \ \text{Kc/kg}$

2•125+B•100 = 110 •(2+B)

10B = 30

B = 3

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