Angles of a hexagon

Find the interior angles of a hexagon if the sizes of the angles form an arithmetic sequence and the smallest angle is 70°.

Correct result:

A =  70 °
B =  90 °
C =  110 °
D =  130 °
E =  150 °
F =  170 °

Solution:

A=70=70
s=180 (62)=720 A+B+C+D+E+F=s A+(A+d)+(A+2d)+(A+3d)+(A+4d)+(A+5d)=s 6A+15d=s=720  d=s6 A15=7206 7015=20 B=A+d=70+20=90
C=B+d=90+20=110
D=C+d=110+20=130
E=D+d=130+20=150
F=E+d=150+20=170=170   Verifying Solution:  s2=A+B+C+D+E+F=70+90+110+130+150+170=720



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