# Circle - AG

Find the coordinates of circle and its diameter if its equation is:

${x}^{2}+{y}^{2}-6x-4y=36$

Correct result:

x1 =  3
y1 =  2
D =  14

#### Solution:

${y}_{1}=2$

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Showing 1 comment:
Math student
why is x =3 =0?

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