# Find parameters

Find parameters of the circle in the plane - coordinates of center and radius:

$x2+(y-3)2=14$

Correct result:

x0 =  0
y0 =  3
r =  3.7417

#### Solution:

$(x-x_{0})^2+(y-y_{0})^2=r^2 \ \\ (x-0)^2+(y-3)^2=14 \ \\ \ \\ x_{0}=0$
$y_{0}=3$
$r=\sqrt{14}=3.7417$ We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you! Tips to related online calculators
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