Find parameters

Find parameters of the circle in the plane - coordinates of center and radius:

x2+(y3)2=14x2+(y-3)2=14


Correct result:

x0 =  0
y0 =  3
r =  3.7417

Solution:

(xx0)2+(yy0)2=r2 (x0)2+(y3)2=14  x0=0(x-x_{0})^2+(y-y_{0})^2=r^2 \ \\ (x-0)^2+(y-3)^2=14 \ \\ \ \\ x_{0}=0
y0=3y_{0}=3
r=14=3.7417



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