Find parameters

Find parameters of the circle in the plane - coordinates of center and radius:

x2+(y3)2=14x2+(y-3)2=14


Result

x0 =  0
y0 =  3
r =  3.742

Solution:

(xx0)2+(yy0)2=r2 (x0)2+(y3)2=14  x0=0(x-x_{ 0 })^2+(y-y_{ 0 })^2 = r^2 \ \\ (x-0)^2+(y-3)^2 = 14 \ \\ \ \\ x_{ 0 } = 0
y0=3y_{ 0 } = 3
r=14=143.7417=3.742r = \sqrt{ 14 } = \sqrt{ 14 } \doteq 3.7417 = 3.742



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For Basic calculations in analytic geometry is helpful line slope calculator. From coordinates of two points in the plane it calculate slope, normal and parametric line equation(s), slope, directional angle, direction vector, the length of segment, intersections the coordinate axes etc.
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