In a rectangle with sides, 8 and 9 mark the diagonal. What is the probability that a randomly selected point within the rectangle is closer to the diagonal than any side of the rectangle?

Correct answer:

p =  41.5 %

Step-by-step explanation:

a=8 b=9  c2 = a2+b2 c=a2+b2=82+92=14512.0416  S1=2a b=28 9=36  r=a+b+c2 S1=8+9+12.04162 362.4792 S2=2r c=22.4792 12.041614.9268  p=100 S1S2=100 3614.9268=41.5%

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