Chocolate roll

The cube of 5 cm chocolate roll weighs 30 g. How many calories will contain the same chocolate roller of a prism shape with a length of 0.5 m whose cross section is an isosceles trapezoid with bases 25 and 13 cm and legs 10 cm. You know that 100 g of this roll is 520 kcal.
1. Draw a picture of the roll and determine what quantity to count.
2. Write the formula for the magnitude from point 1 and determine what you know.
3. Calculate the Sp and the magnitude from point 1.
4. Calculate cube volume.
5. Calculate the weight of the roll (over the triple).
6. Determine the number of calories in the roll.

Result

x =  9484.8 kcal

Solution:

a=5 cm m1=30 g V1=a3=53=125 cm3 r=m1/V1=30/125=625=0.24 g/cm3 c=50 cm s=(25−13)/2=6 cm h=102−s2=102−62=8 cm S1=h⋅ (25+13)/2=8⋅ (25+13)/2=152 cm2 V2=S1⋅ c=152⋅ 50=7600 cm3 q=520/100=265=5.2 x=q⋅ r⋅ V2=5.2⋅ 0.24⋅ 7600=474245=9484.8 kcala=5 \ \text{cm} \ \\ m_{1}=30 \ \text{g} \ \\ V_{1}=a^3=5^3=125 \ \text{cm}^3 \ \\ r=m_{1}/V_{1}=30/125=\dfrac{ 6 }{ 25 }=0.24 \ \text{g/cm}^3 \ \\ c=50 \ \text{cm} \ \\ s=(25-13)/2=6 \ \text{cm} \ \\ h=\sqrt{ 10^2-s^2 }=\sqrt{ 10^2-6^2 }=8 \ \text{cm} \ \\ S_{1}=h \cdot \ (25+13)/2=8 \cdot \ (25+13)/2=152 \ \text{cm}^2 \ \\ V_{2}=S_{1} \cdot \ c=152 \cdot \ 50=7600 \ \text{cm}^3 \ \\ q=520/100=\dfrac{ 26 }{ 5 }=5.2 \ \\ x=q \cdot \ r \cdot \ V_{2}=5.2 \cdot \ 0.24 \cdot \ 7600=\dfrac{ 47424 }{ 5 }=9484.8 \ \text{kcal}

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