Straight-line 42511

The lady and the gentleman run toward each other in an even, straight-line motion. The lady runs at a speed of 25.2 km/h, and the man at a speed of 18 km/h. When they are 300m apart, we start timing. How long before the lady and the man fall into each other's arms?

Correct answer:

t =  25 s

Step-by-step explanation:

v1=25.2 km/h m/s=25.2:3.6  m/s=7 m/s v2=18 km/h m/s=18:3.6  m/s=5 m/s s=300 m  v=v1+v2=7+5=12 m/s  s=vt t=s/v=300/12=25 s



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