Minimum of sum

Find a positive number that the sum of the number and its inverted value was minimal.

Correct result:

x =  1


f(x)=x+1/x x>0 f(x)=11/x2 11/x2=0 x21=0  x21=0  a=1;b=0;c=1 D=b24ac=0241(1)=4 D>0  x1,2=b±D2a=±42 x1,2=±22 x1,2=±1 x1=1 x2=1   Factored form of the equation:  (x1)(x+1)=0 x=x1=1

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