# Derivative problem

The sum of two numbers is 12. Find these numbers if:
a) The sum of their third powers is minimal.
b) The product of one with the cube of the other is maximal.
c) Both are positive and the product of one with the other power of the other is maximal.

a1 =  6
b1 =  6
a2 =  3
b2 =  9
a3 =  4
b3 =  8

### Step-by-step explanation:

${b}_{1}=12-{a}_{1}=12-6=6$
${b}_{2}=12-{a}_{2}=12-3=9$

Our quadratic equation calculator calculates it.

${b}_{3}=12-{a}_{3}=12-4=8$ Did you find an error or inaccuracy? Feel free to write us. Thank you! Tips to related online calculators

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