Metal balls

Four metal balls with a diameter of 5 cm are placed in a measuring cylinder with an inner diameter of 10 cm. What is the smallest water volume to be poured into the cylinder so that all balls are below the water level?

Correct answer:

V =  470.9871 cm3

Step-by-step explanation:

D=10 cm R=D/2=10/2=5 cm  n=4  d=5 cm r=d/2=5/2=52=2.5 cm  V1=43 π r3=43 3.1416 2.5365.4498 cm3  h1=32 (2 r)=32 (2 2.5)4.3301 cm  h=h1+2 r=4.3301+2 2.59.3301 cm  V2=π R2 h=3.1416 52 9.3301732.7865 cm3  V=V2n V1=732.78654 65.4498=470.9871 cm3



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