Hollow sphere

The hollow ball's volume is 3432 cm3. What is its internal radius when the wall thickness is 3 cm?

Correct answer:

r =  8 cm

Step-by-step explanation:

V=3432 cm3 h=3 cm V = V1  V2 V1 = 4/3   π   (r+h)3 V2 = 4/3   π   r3 3/4/π V = (r+h)3  r3 k=3/4/π V=3/4/3.1416 3432819.3296 9r2+27r+27=819.3296  9r2+27r792.33=0  a=9;b=27;c=792.33 D=b24ac=27249(792.33)=29252.8656 D>0  r1,2=2ab±D=1827±29252.87 r1,2=1.5±9.501927 r1=8.00192729 r2=11.00192729 r>0 r=[r1]=[8.0019]=8=8 cm V1=4/3π (r+h)3=4/3 3.1416 (8+3)35575.2798 V2=4/3π r3=4/3 3.1416 832144.6606 V3=V1V2=5575.27982144.66063430.6192

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